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Chapter 31: Q. 38 (page 902)

FIGUREP31.38shows the voltage across a 0.10mFcapacitor. Draw a graph showing the displacement current through the capacitor as a function of time.


Short Answer

Expert verified

Required graph is given below.

Step by step solution

01

Given information

We are given thatQ=CV

So, I=dQdt=CdVdt

02

Step2:Simplify

So, it will roughly follow the slope of the voltage curve

So, from 0to 1:dVdt=1001uS

So, I=0.1×100=10A

from 1to 2:dVdt=0

so I=0

from 2to 4: dVdt=1002uS

So, I=0.1×50=-5A


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