Chapter 31: Q. 38 (page 902)

$F I G U R E P 31.38$ shows the voltage across a $0.10 m F$ capacitor. Draw a graph showing the displacement current through the capacitor as a function of time.

Short Answer

Expert verified

Required graph is given below.

Step by step solution

Given information

We are given that $Q = C V$

So, $I = \frac{d Q}{d t} = C \frac{d V}{d t}$

Step2:Simplify

So, it will roughly follow the slope of the voltage curve

So, from $0$ to $1$ : $\frac{d V}{d t} = \frac{100}{1} u S$

So, $I = 0.1 \times 100 = 10 A$

from $1$ to $2$ : $\frac{d V}{d t} = 0$

so $I = 0$

from $2$ to $4$ : $\frac{d V}{d t} = \frac{100}{2 u S}$

So, $I = 0.1 \times 50 = - 5 A$

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$F I G U R E P 31.38$ shows the voltage across a $0.10 m F$ capacitor. Draw a graph showing the displacement current through the capacitor as a function of time.

Short Answer

Step by step solution

Given information

Step2:Simplify

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FIGUREP31.38shows the voltage across a 0.10mFcapacitor. Draw a graph showing the displacement current through the capacitor as a function of time.

Short Answer

Step by step solution

Given information

Step2:Simplify

One App. One Place for Learning.

Most popular questions from this chapter

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$F I G U R E P 31.38$ shows the voltage across a $0.10 m F$ capacitor. Draw a graph showing the displacement current through the capacitor as a function of time.