Assume that a 7.0-cm-diameter, 100Wlight bulb radiates all its energy as a single wavelength of visible light. Estimate the electric and magnetic field strengths at the surface of the bulb.

Short Answer

Expert verified

At surface of the bulb,

Electric field strength is 2.21×103vm.

Magnetic field strength is7.3×10-6T.

Step by step solution

01

Calculation for intensity

Given info:

Diameter is 7.0cm.

Power is100W.

Intensity is,

Iavg=PA

Where,

Power=100W

localid="1649957590468" Iavg=100W4π3.5×10-22m2

Iavg=65×102W/m2

02

Calculation of Electric field strength

Electric field is,

Eo=2×Iavgc×εO1/2

localid="1649960680664" Eo=2×65×102Wm23×108ms×8.85×10-12c2Nm21/2

Eo=2.21×103vm

03

Calculation for magnetic field strength

Magnetic field is,

B0=E0c

B0=2.21×103vm3×108ms

B0=7.3×10-6T

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Study anywhere. Anytime. Across all devices.

Sign-up for free