A cube of water 10 cm on a side is placed in a microwave beam having E0=11kV/m. The microwaves illuminate one face of the cube, and the water absorbs 80%of the incident energy. How long will it take to raise the water temperature by 50˚C?.Assume that the water has no heat loss during this time.

Short Answer

Expert verified

The raise of the water temperature isΔt=162s

Step by step solution

01

Definition of Electromagnetic fields and Waves:

A charge near its surroundings produces an electric field, which is a force. When other charges are brought near this field, they are subjected to this force. N/C (Force/Charge) is the SI unit for electric fields.

02

Given values:

A=0.10mE0=11kV/mT=50˚

03

Substitute the rate of energy values into equation:

P=(80%)IA

P=(0.80)cεo2Eo2A

P=(0.80)3×108m/s8.85×10-12C2/N·m2211×103V/m2(0.10m)

localid="1649933986875" P=1.29kW

04

Equation:

Now, Find value for E:

ΔE=mcΔT

ΔE=(0.10m)31000kg/m34186J/kg/C50°C

ΔE=2.10×105J

05

Substitute the values in equation: 

Finally, find the values for t:

Δt=ΔEP

Δt=2.10×105J1.29×10-3Wt=162s

06

Final Result:

The change in the quantity of water ist=162s.

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