Consider current Ipassing through a resistor of radius r, length L, and resistance R.

a. Determine the electric and magnetic fields at the surface of the resistor. Assume that the electric field is uniform throughout, including at the surface.

b. Determine the strength and direction of the Poynting vector at the surface of the resistor.

c. Show that the flux of the Poynting vector (i.e., the integral of SdA) over the surface of the resistor is I2R. Then give an interpretation of this result.

Short Answer

Expert verified

a) The electric and magnetic fields at the surface of the resistor, JdA=iJ=iπa2

b) The strength and direction of the Poynting vector at the surface of the resistor,Eπa2L=4πkQenclosed

c)The flux of the Poynting vector over the surface of the resistor,Q=L2iaρ2k

Step by step solution

01

Calculate the fields which is on the surface of resistor. (part a)

a.

The charge changes with respect to time is,

q(t)=t0t1idt

JdA=iJ=iπa2

Charge enclosed is,

Qenclosed=JL

Qenclosed=JL

By above equation,

B=μ0I2πa

02

find Poynting vector's strengths and directions (part b)

b)

Using ohms law,

R=ρLπa2

Poynting vector shown as,

S=Eμ0×B

By above equation, you got

EdA=4πkQenclosedEπa2L=4πkQenclosed i=dqdt.

03

The flux of Poynting vector (part c)

c)

Multiplication of electric field and magnetic field of resistors gives flux of the poynting vector,

EB=i2ρLπa2E=2ρLiμ0a

Q=L2iaρ2k

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

Large quantities of dust should have been left behind after the creation of the solar system. Larger dust particles, comparable in size to soot and sand grains, are common. They create shooting stars when they collide with the earth's atmosphere. But very small dust particles are conspicuously absent. Astronomers believe that the very small dust particles have been blown out of the solar system by the sun. By comparing the forces on dust particles, determine the diameter of the smallest dust particles that can remain in the solar system over long periods of time. Assume that the dust particles are spherical, black, and have a density of 2000kg/m3. The sun emits electromagnetic radiation with power 3.9×1026W.

The intensity of sunlight reaching the earth is 1360W/m2. Assuming all the sunlight is absorbed, what is the radiation pressure force on the earth? Give your answer (a) in newtons and (b) as a fraction of the sun's gravitational force on the earth.

An electron travels with v=5.0×106i^msthrough a point in space where E=(2.0×105i^-2.0×105j^)Vmand B=-0.10k^T. What is the force on the electron?

The radar system at an airport broadcasts 11GHzmicrowaves with 150kW of power. An approaching airplane with a 31m2 cross section is 30Km away. Assume that the radar broadcasts uniformly in all directions and that the airplane scatters microwaves uniformly in all directions. What is the electric field strength of the microwave signal received back at the airport 200μslater?

2. Sharon drives her rocket through the magnetic field of FIGURE Q31.2 traveling to the right at a speed of 1000m/sas measured by Bill. As she passes Bill, she shoots a positive charge backward at a speed of 1000m/srelative to her.

a. According to Bill, what kind of force or forces act on the charge? In which directions? Explain.

b. According to Sharon, what kind of force or forces act on the charge? In which directions? Explain.

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free