The intensity of an electromagnetic wave is 10W/m2. What will the intensity be if:

a. The amplitude of the electric field is doubled?

b. The amplitude of the magnetic field is doubled?

c. The amplitudes of both the electric and the magnetic fields are doubled?

d. The frequency is doubled?

Short Answer

Expert verified

(a) Since IE02, the new intensity is40W/m2

(b) For an electromagnetic waveE0B0, so 40W/m2.

(c) When it comes to electromagnetic waves, increasing one amplitude necessitates doubling the other, so 40W/m2.

(d) Since the amplitudes are unaffected by changing the frequency, the intensity remains constant at 10W/m2.

Step by step solution

01

Amplitude of electric field

The energy crossing per second per unit area parallel to the direction of propagation of electromagnetic waves is defined as the intensity of electromagnetic waves. where c is the electromagnetic wave's velocity.

02

Energy in Electromagnetic waves

The energy of such a wave is proportional of its amplitude (E2 or B2). This really is valid for waves on strings, water waves, and sound waves, where amplitude and pressure are proportional. The maximum field strength of the electric and magnetic is the amplitude in electromagnetic waves.

As a conclusion, the energy carried by such an electromagnetic wave and also its intensity Iis proportional to E2and B2.In fact, the increasing quality wave of such a continuous oscillatory electromagnetic field is given by

Iave=cϵ0E022

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