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Chapter 31: Q.30 (page 902)

What electric field strength and direction will allow the proton in FIGURE P31.30 to pass through this region of space without being deflected?

Short Answer

Expert verified

The region of space without being deflectedE=2×105V/m

Step by step solution

01

Given

v=2×107m/s

B=0.01T

02

Right Hand Rule

Magnetic force occurs downward if using its right hand rule.

As a reason, due to the electric field, equal and opposite charges exist upward, but electron are not deflected. As a function, the direction of the electric field is also downward.

Fe=FB

qE=qvB

E=vB

E=2×107×10−2

E=2×105V/m

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