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Chapter 30: Q.32 (page 871)

An LC circuit has a 10 mH inductor. The current has its maximum value of 0.60 A at t = 0 s. A short time later the capacitor reaches its maximum potential difference of 60 V. What is the value of the capacitance?

Short Answer

Expert verified

The value of capacitance is10-6F.

Step by step solution

01

Given information

We have given that, an LC circuit has a 10 mH inductor, and it has 0.60 A current at t = 0 s. A short time later the capacitor reaches its maximum potential difference of 60 V.

02

Step 1.

We know that energy of capacitor = energy of inductor.

12LI2=12CV2

Here, L = Inductance

I = Current

C = Capacitance

V = Potential difference

We will use this formula to calculate the value of capacitor.

03

Step 2.

Substituting the values in the formula :

12(10×10-3H)(0.6A)2=12C(60V)2

C=(10×10-3H)×(0.6A×0.6A)60V×60V

C=10-6F

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