A nuclear power plant draws 3.0×106L/min of cooling water from the ocean. If the water is drawn in through two parallel,3.0m-diameter pipes, what is the water speed in each pipe?

Short Answer

Expert verified

Therefore, the speed of the water through each pipe is3.53m/s

Step by step solution

01

Step :1 Introduction 

The volume from one pipe is given follow

Vt=3.0×106L/min2

The conversion is given as follows:

Vt=1.5×106Lmin103m360s

=25m3s

02

Step :2 Explanation 

The area of the pipe is given as follows:

A=πd22

Here, dis the diameter of the pipe.

Substitute 3mfor d.

A=π3m22

=7.065m2

03

Step :3  Expression of speed

The expression for the speed of the water flowing through the pipe related to the volume flow rate is given as follows:

v=ViA

Substitute 25m3sforV1and7.065m2forA

v=25m3s7.065m2

=3.53m/s

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