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Chapter 5: Q 12. (page 128)

FIGURE shows an acceleration-versus-force graph for a 200 g object. What force values go in the blanks on the horizontal scale?

Short Answer

Expert verified

(a) F= 1 N

(b) F= 2 N

Step by step solution

01

Step 1.Given information

here graph is given which shows an acceleration-versus-force graph for a 200 g object. and when you show the graph the value of force is missing so using Newton second law find the value of force in horizontal scale.

02

Step 2 

Newton second Law say that force is directly proportional to rate of change of momentum

Fαdp→dtF=mdvdtF=ma...........(1)

03

Step 3 

Consider the first condition where mass is 0.2 kg and acceleration 5 m/s2

substitute value of mass and acceleration in equation (1)

F1=ma1F1=0.2kg×5m/s2F1=1N

04

Step 4 

Consider the first condition where mass is 0.2 kg and acceleration 10 m/s2

substitute value of mass and acceleration in equation (1)

F2=ma2F2=0.2kg×10m/s2F2=2N

Therefor, two forces value are 1 N and 2 N.

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