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Chapter 5: Q.13b (page 128)

FIGURE EX5.13 shows an acceleration-versus-force graph for a 500gobject. What acceleration values go in the blanks on the vertical scale?

Short Answer

Expert verified

a.The acceleration of the object is2.0m/s2.

Step by step solution

01

Part.a.

Newton's second law states that the acceleration acting on an object is directly proportional to the force acting on the object and inversely proportional to the mass of the object.

a=Fm

Here, Fis the force acting on the object, and mis the mass of the object.

02

Step.2

The figure is shown below

From the figure at point(a), the force is2N

Convert the unit of mass fromto

m=500g10−3kg1g=500×10−3kg

Substitute 2Nfor F, and 500×10−3kgfor m.

a=2N500×10−3kg=4.0m/s2

Therefore, the acceleration of the object is4.0m/s2.

03

Part.b.

From the figure at point (b), the force is1N

The acceleration acting on the object is,

a=Fm

Substitute 1Nfor F, and 500×10−3kgfor m.

a=1N500×10−3kg=2.0m/s2

Therefore, the acceleration of the object is2.0m/s2.

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