Bulbs A, B, and C in FIGURE Q28.10 are identical, and all are glowing.

a. Rank in order, from most to least, the brightnesses of the three bulbs. Explain.

b. Suppose a wire is connected between points 1 and 2. What happens to each bulb? Does it get brighter, stay the same, get dimmer, or go out? Explain

Short Answer

Expert verified

a. A>B=C

b. Bulb A gets brighter in this example, whereas bulbs B and C go out.

Step by step solution

01

Given information and formula used 

Given :

Theory used :

a. The resistors in series have the same current.

b. The current through the resistor determines how much power passes through it

02

Ranking in order the brightnesses of the bulbs

(a) The resistors in series have the same current.

As a result, the current flowing through bulb A is the same as the current flowing through the two bulbs B and C combined. Because the current is greater, the brightness of bulb A is greater than that of C and B.

The current will be the same for both bulbs C and B because they are similar. As a result, C and B have the same brightness.

Hence, we rank the bulbs' brightness by A>B=C

03

Determining if the bulbs get brighter, stay the same, get dimmer, or go out 

(b) The current through the resistor determines how much power passes through it. When a wire is connected between points 1 and 2, current flows through this wire rather than bulb B or C.

As a result, there is no current flowing through bulbs B and C.

Bulb A gets brighter in this example, whereas bulbs B and C go out.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

The capacitor in an RC circuit is discharged with a time constant of 10ms. At what time after the discharge begins are

(a) the charge on the capacitor reduced to half its initial value and

(b) the energy stored in the capacitor reduced to half its initial value?

How much power is dissipated by each resistor in FIGURE EX28.8?

The five identical bulbs in FIGURE EX28.11are all glowing. The battery is ideal. What is the order of brightness of the bulbs, from brightest to dimmest? Some may be equal.

A.P=T>Q=R=S

B.P>Q=R=S>T

C.P=T>Q>R=S

D.P>Q>T>R=S

What is the magnitude of the potential difference across each resistor in FIGURE EX28.6?

An oscillator circuit is important to many applications. A simple oscillator circuit can be built by adding a neon gas tube to an RC circuit, as shown in figureCP28.83. Gas is normally a good insulator, and the resistance of the gas tube is essentially infinite when the light is off. This allows the capacitor to charge. When the capacitor voltage reaches a value Von, the electric field inside the tube becomes strong enough to ionize the neon gas. Visually, the tube lights with an orange glow. Electrically, the ionization of the gas provides a very-low-resistance path through the tube. The capacitor very rapidly (we can think of it as instantaneously) discharges through the tube and the capacitor voltage drops. When the capacitor voltage has dropped to a value Voff, the electric field inside the tube becomes too weak to sustain the ionization and the neon light turns off. The capacitor then starts to charge again. The capacitor voltage oscillates between Voff, when it starts charging, and Von, when the light comes on to discharge it.

a. Show that the oscillation period is

T=RCinε-Voffε-Von

b. A neon gas tube has Von=80VandVoff=20V. What resistor value should you choose to go with a 10μfcapacitor and a 90Vbattery to make a 10Hzoscillator?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free