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Chapter 28: Q. 41 (page 792)

Two 75W(120V) lightbulbs are wired in series, then the combination is connected to a 120V supply. How much power is dissipated by each bulb?

Short Answer

Expert verified

Power dissipated by each bulb is18.45W.

Step by step solution

01

Given information

We have given,

For one bulb the power dissipation is 75Wat 120V.

We have to find the power dissipated by the each bulb.

02

Simplify

We know that Power dissipated by one bulb only without connected the other bulb in circuit is given by,

P=V2RR=V2PR=(102)275=192Ω

then total resistance in the circuit after connected both the bulb will be equal to the equivalent resistance,

Req=2×192=384Ω

Due to equivalent resistances in series then current flowing in the circuit will be after connecting both bulb,

IReq=VI=120384=0.31A

Then power dissipated by one bulb in the circuit will be

P=I2R=(0.31)2192=18.45W

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Most popular questions from this chapter

The circuit of FIGURE has two resistors, with R1>R2. Which of the two resistors dissipates the larger amount of power? Explain.

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