The circuit of FIGURE has two resistors, with $R_1>R_2$. Which of the two resistors dissipates the larger amount of power? Explain.

The circuit that contains two resistors has relation of $R_1>R_2$

The expression for power is,

$P=\frac{v^2}{R}$

where, $V$is the voltage and $R$is the resistance.

In the diagram below, the resistors are linked in parallel:

The two resistances $R_1$and $R_2$are coupled in a parallel combination in this diagram. We know that when resistances are coupled in a parallel configuration, the potential difference between them is the same.

Thus can deduce from the preceding calculation of power that power is inversely related to resistance.

The power dissipated through the resistor decreases as the resistance increases, and vice versa.

$R_1>R_2$is the specified condition.

Because the resistor $R_1$has a greater value, the power wasted through it will be reduced.

As a result, the power lost through the resistance $R_2$will be greater.