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Chapter 28: Q. 50 (page 792)
A lightbulb is in series with a resistor. The lightbulb dissipates when this series circuit is connected to a battery. What is the current through the lightbulb? There are two possible answers; give both of them.
The current through the light bulb is
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For the circuit shown in FIGURE P28.62, find the current through and the potential difference across each resistor. Place your results in a table for ease of reading.
The capacitor in begins to charge after the switch closes at . Analyze this circuit and show that ,where.
An oscillator circuit is important to many applications. A simple oscillator circuit can be built by adding a neon gas tube to an RC circuit, as shown in . Gas is normally a good insulator, and the resistance of the gas tube is essentially infinite when the light is off. This allows the capacitor to charge. When the capacitor voltage reaches a value Von, the electric field inside the tube becomes strong enough to ionize the neon gas. Visually, the tube lights with an orange glow. Electrically, the ionization of the gas provides a very-low-resistance path through the tube. The capacitor very rapidly (we can think of it as instantaneously) discharges through the tube and the capacitor voltage drops. When the capacitor voltage has dropped to a value , the electric field inside the tube becomes too weak to sustain the ionization and the neon light turns off. The capacitor then starts to charge again. The capacitor voltage oscillates between , when it starts charging, and , when the light comes on to discharge it.
a. Show that the oscillation period is
b. A neon gas tube has . What resistor value should you choose to go with a capacitor and a battery to make a oscillator?
Bulbs A and B in FIGURE Q28.11 are identical, and both are glowing. Bulb B is removed from its socket. Does the potential difference between points 1 and 2 increase, stay the same, decrease, or become zero? Explain.
In FIGURE , what is the magnitude of the current in the wire to the right of the junction? Does the charge in this wire flow to the right or to the left?
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