The ammeter in FIGURE P28.52 reads3.0A. Find I1,I2,and ε.

Short Answer

Expert verified

The value of

I1=5AI2=8Aε=14V.

Step by step solution

01

Given information

We have given,

Ammeter reading = 3A

We have to find the value ofI1,I2,ε.

02

Simplify

Using the Kirchhoff voltage law in the upper loop

-9V+3×I1=2×3AI1=9+63I1=5A

Using Kirchhoff current rule at the node and substitute the value ofI1.

localid="1649416745087" I2=I1+3AI2=5A+3A=8A

Using Kirchhoff voltage rule in the lower loop

localid="1649416765380" (2×3A)-ε+(1×I2)=0ε=6+8ε=14V

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A 12 V car battery dies not so much because its voltage drops but because chemical reactions increase its internal resistance. A good battery connected with jumper cables can both start the engine and recharge the dead battery. Consider the automotive circuit of FIGURE P28.65.

a. How much current could the good battery alone drive through the starter motor?

b. How much current is the dead battery alone able to drive through the starter motor?

c. With the jumper cables attached, how much current passes through the starter motor?

d. With the jumper cables attached, how much current passes through the dead battery, and in which direction?

You have a 2.0resistor, a 3.0resistor, a 6.0resistor, and a 6.0Vbattery. Draw a diagram of a circuit in which all three resistors are used and the battery delivers 9.0 W of power.

A circuit you’re building needs an ammeter that goes from 0mAto a full-scale reading of 50mA. Unfortunately, the only ammeter in the storeroom goes from 0μAto a full-scale reading of only 500μA. Fortunately, you’ve just finished a physics class, and you realize that you can make this ammeter work by putting a resistor in parallel with it, as shown in FIGURE P28.57. You’ve measured that the resistance of the ammeter is50, not the0of an ideal ammeter.

a. What value of R must you use so that the meter will go to full scale when the current I is50mA?

b. What is the effective resistance of your ammeter?

How much power is dissipated by each resistor in FIGURE EX28.8?

What are the emf and internal resistance of the battery in FIGURE P28.46?

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free