Chapter 28: Q. 52 (page 792)

The ammeter in FIGURE P28.52 reads $3.0 A$ . Find $I_{1}, I_{2},$ and $ε .$

Short Answer

Expert verified

The value of

$I_{1} = 5 A I_{2} = 8 A ε = 14 V .$

Step by step solution

Given information

We have given,

Ammeter reading = $3 A$

We have to find the value of $I_{1}, I_{2}, ε .$

Simplify

Using the Kirchhoff voltage law in the upper loop

$- 9 V + 3 Ω \times I_{1} = 2 Ω \times 3 A I_{1} = \frac{9 + 6}{3} I_{1} = 5 A$

Using Kirchhoff current rule at the node and substitute the value of $I_{1} .$

localid="1649416745087" $I_{2} = I_{1} + 3 A I_{2} = 5 A + 3 A = 8 A$

Using Kirchhoff voltage rule in the lower loop

localid="1649416765380" $(2 Ω \times 3 A) - ε + (1 Ω \times I_{2}) = 0 ε = 6 + 8 ε = 14 V$

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The ammeter in FIGURE P28.52 reads $3.0 A$ . Find $I_{1}, I_{2},$ and $ε .$

Short Answer

Step by step solution

Given information

Simplify

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The ammeter in FIGURE P28.52 reads3.0A. Find I1,I2,and ε.

Short Answer

Step by step solution

Given information

Simplify

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Geometrical and Physical Optics

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Study anywhere. Anytime. Across all devices.

The ammeter in FIGURE P28.52 reads $3.0 A$ . Find $I_{1}, I_{2},$ and $ε .$