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Chapter 28: Q. 56 (page 793)

A battery is a voltage source, always providing the same potential difference regardless of the current. It is possible to make a current source that always provides the same current regardless of the potential difference. The circuit in FIGURE P28.56 is called a current divider. It sends a fraction of the source current to the load. Find an expression for Iloadin terms of R1,R2and Isource.You can assume that the load’s resistance is much less thanR2.

Short Answer

Expert verified

The expression of the load current will be

Iload=R1R1+R2×Isource

Step by step solution

01

Given information

We have given,

the circuit as shown in above with load resistance has low value.

We have to find the current through the load in terms of resistances and current source.

02

Simplify

Since the load resistance given in the circuit has low value than we can neglected it.

Using the Kirchhoff voltage law in the right loop

I1R1-IloadR2=0Iload=I1R1R2

using the Kirchhoff current rule at one node

Isource=I1+IloadIsource=IloadR2R1+IloadIload=R1R1+R2×Isource

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