The electric field must be zero inside a conductor in electrostatic equilibrium, but not inside an insulator. It turns out that we can still apply Gauss's law to a Gaussian surface that is entirely within an insulator by replacing the right-hand side of Gauss's law, Qin/ϵ0, with Qin/ϵ, where ϵ is the permittivity of the material. (Technically,ϵ0 is called the vacuum permittivity.) Suppose that a 50nC point charge is surrounded by a thin, 32-cm-diameter spherical rubber shell and that the electric field strength inside the rubber shell is2500N/C . What is the permittivity of rubber?

Short Answer

Expert verified

Permittivity of rubber is6.2×10-11C2/N·m2.

Step by step solution

01

Formula for permittivity

The amount of electric field that flows through a closed surface is known as the electric flux.

The electric field travelling through a surface is proportional to the charge within the surface, according to Gauss' law.

Electric flux,

Φe=EA=Qinε

ε=QinEA

Area is,

A=4πr2

02

Calculation for permittivity

Radius,

r=d2

=32cm2=16cm

Substitute all of the values.

ε=Qin4πr2E

The following is the inert charge:

Qin=(50nC)1×10-9CnC=50×10-9C

Then,

ε=Qin4πr2E

=50×10-9C4π(0.16m)2(2500N/C)

=6.2×10-11C2/N·m2

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