A heat engine extracts 55KJof heat from the hot reservoir each cycle and exhausts 40KJof heat. What are (a) the thermal efficiency and (b) the work done per cycle?

Short Answer

Expert verified

(a) The thermal efficiency is 27 %

(b) The work done per cycle is 15kJ.

Step by step solution

01

Step : 1 Introduction (part a)

(a) The ratio of work done per cycle to amount of heat retrieved from the warm reservoir Q1is the efficiency of the engine. The difference between the extracted heat and the work done per cycle equals the work done per cycle. Q1and exhausted heat Q2so we have

localid="1649241559768" η=WQ1

work done W per cycle is the difference of heat extracted and heat dumped into cold reservoir .

W=55kJ-40kJ.=15kJ.

Substitute 15 kJ for W and 55 kJ for Q1in the equation of efficiency above.

η=15kJ55kJ×100=27%

Q1
02

Step :2 Explanation (part b)

(b) The work done per cycle, as explained is difference of heat extracted and heat dumped into cold reservoir.

W=Q1Q2

localid="1649242118588" =55kJ-40kJ=15kJ

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