Rank in order, from largest to smallest, the momenta (px)ato (px)eof the objects in FIGURE Q11.1.

Short Answer

Expert verified

Rank in order, from largest to smallest ispb>pa=pc=pe>pd.

Step by step solution

01

Given information

We have given that the momenta(px)ato(px)eof thew object.

We need to find that the rank in order , from largest to smallest.

02

Simplify

An object with mass mand moves with speed vhaving momentum p, this momentum is a vector and it is the product of the object mass and its velocity. A large mass of large velocity momentum. The momentum is given by equation (11,3)in the form

px=mv(1)

Object (a):

The mass of the object is ma=20gand velocity va=1m/s. We can use equation (1)and plug the values for 20gand 1m/sto get the momentum pa

pa=mava=(20×10-3kg)(1m/s)=0.02kg(m/s)

Object (b):

The mass of object is mb=20gand velocity vb=2m/s. We can use equation (1)and putting the values for 20gand 2m/sto get momentum pb

pb=mbvb=(20×10-3kg)(2m/s)=0.04kg(m/s)

03

Simplify

Object (c):

Mass of the object is mc=10gand velocity vc=2m/s. We can use equation (1)and putting the values for 10gand 2m/sto get the momentum pC

Pc=mcvc=(10×10-3kg)(2m/s)=0.02kg(m/s)

Object (d):

Mass of the object is md=10gand velocity vd=1m/s. We can use equation (1)and putting the values for10gand 1m/sto get the momentum pd

pd=mdvd=(10×10-3kg)(1m/s)=0.01kg(m/s)

Object (e):

Mass of the object is me=200gand velocity ve=0.1m/s. We can use equation (1)and putting the values for 200gand 0.1m/sto get the momentum pe

Pe=meve=(200×10-3kg)(0.1m/s)=0.02kg(m/s)

Finally, the order from the largest to the smallest is

pb>pa=pc=pe>pd

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