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Chapter 11: Q. 18 (page 287)

A 300gbird flying along at 6.0m/ssees a 10g insect heading straight toward it at a speed of 30m/s. The bird opens its mouth wide and enjoys a nice lunch. What is the bird’s speed immediately after swallowing?

Short Answer

Expert verified

The final speed of the bird is4.8m/s.

Step by step solution

01

Given information

We have given,

Speed of bird =6m/s

Speed of insect =30m/s

Mass of bird =300g

Mass of insect =10g

We have to find the bird's final speed after he eat the insect.

02

Simplify

We know from the conservation of momentum that in the colleen the momentum before the Collison of the system will be same after the Collison.

momentum before Collison = Momentum after Collison

PI=PF

since initial momentum will be the sum of momentums of the bird and insect individuals.

PI=mBVB+mI+VIPI=0.3kg×6m/s+0.01kg×-30m/sPF=(0.3+0.01)kg×V

THEN,

PF=PI0.31kg×V=(0.18-0.3)V=4.8m/s

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Most popular questions from this chapter

A tennis player swings her 1000g racket with a speed of 10 m/s. She hits a 60g tennis ball that was approaching her at a speed of 20 m/s . The ball rebounds at 40m/s.

a. How fast is her racket moving immediately after the impact? You can ignore the interaction of the racket with her hand for the brief duration of the collision.

b. If the tennis ball and racket are in contact for 10 m/s, what is the average force that the racket exerts on the ball? How does this compare to the gravitational force on the ball?

A proton (mass 1 u) is shot toward an unknown target nucleus at a speed of 2.50×106 m/s. The proton rebounds with its speed reduced by 25% while the target nucleus acquires a speed of 3.12×105 m/s. What is the mass, in atomic mass units, of the target nucleus?

A two-stage rocket is traveling at 1200 m/s with respect to the earth when the first stage runs out of fuel. Explosive bolts release the first stage and push it backward with a speed of 35 m/s relative to the second stage. The first stage is three times as massive as the second stage. What is the speed of the second stage after the separation?

An object at rest explodes into three fragments. FIGURE EX11.32 shows the momentum vectors of two of the fragments. What is the momentum of the third fragment? Write your answer using unit vectors.

0.10kg+0.20kgv1x=(0.10kg)(3.0m/s)12(0.30kg)(0m/s2)+12(3.0N/m)(∆x2)2=12(0.30kg)(v1x)2+12(3.0N/m)(0m)2

a. Write a realistic problem for which this is the correct equation(s).

b. Finish the solution of the problem, including a pictorial representation.
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