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Chapter 11: Q. 22 (page 288)

A 50gmarble moving at 2.0m/s strikes a 20g marble at rest. What is the speed of each marble immediately after the collision?

Short Answer

Expert verified

Marvel of mass 50ghas speed 0.86m/s.

Marvel of mass20ghas speed2.9m/s.

Step by step solution

01

Given information

We have given,

Masses of marvel =50gand20g.

Speed of marvels =2m/sand0m/s.

We have to find their final velocity after collision.

02

Simplify

The given Collison is a elastic collision.

In the elastic Collison the momentum and energy of the system is conserved.

Then conservation of momentum is,

Pi=Pf

Let us consider marvels as marvel 1 of 50gand marvel 2 of 20g.

Then,

Pi=m1v1+m2v2Pi=0.05kg×2m/s+0Pi=0.1kgm/s

and

PF=m1v1f+m2v2f..........(1)

Then using conservation of energy,

localid="1649676035847" K.EI=K.E.FFm1v12+m2v222=m1v1f2+m2v2f22(0.05)(4)=m1v1f2+m2v2f2........................(2)

Using equation (1) AND (2),

v1f=0.86m/sv2f=2.9m/s

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Most popular questions from this chapter

You have been asked to design a “ballistic spring system” to measure the speed of bullets. A spring whose spring constant is k is suspended from the ceiling. A block of mass M hangs from the spring. A bullet of mass m is fired vertically upward into the bottom of the block and stops in the block. The spring’s maximum compression d is measured.

a. Find an expression for the bullet’s speed vB in terms of m, M, k, and d.

b. What was the speed of a data-custom-editor="chemistry" 10gbullet if the block’s mass is data-custom-editor="chemistry" 2.0kgand if the spring, with data-custom-editor="chemistry" k=50N/m, was compressed by data-custom-editor="chemistry" 45cm?

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