A ball of mass m and another ball of mass 3m are placed inside a smooth metal tube with a massless spring compressed between them. When the spring is released, the heavier ball flies out of one end of the tube with speed v0. With what speed does the lighter ball emerge from the other end?

Short Answer

Expert verified

The speed will be -3v0.

Step by step solution

01

Given information 

We have given,

Ball of masses =m,3m

Speed of 3mball =v0

We have to find the speed of ball of mass m.

02

Simplify

Both the balls are initially in the rest then the momentum will be zero initial and also the final due to conservation of momentum of particles.

Then,

Pf=0Pf=m1v1+m2v2=0mv+3mv0=0v=-3v0

Where negative sign for the opposite direction.

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