Chapter 11: Q. 60 (page 290)

Force $F (x) = (10 N) \sin (\frac{2 π t}{4 s})$ is exerted on a 250 g particle during the interval $0 s \leq t \leq 2.0 s$ . If the particle starts from rest, what is its speed at t = 2.0 s?

Short Answer

Expert verified

The speed at $t = 2.0 s e c$ is $50.92 m / s$

Step by step solution

Step 1. Given information

Force expression, $F (x) = (10 N) \sin (\frac{2 π t}{4 s})$

The time variation of force value.

Step 2. Apply and calculate

We apply the impulse-momentum theorem,

$\begin{array}{l} \int_{0}^{2} (10 N) \sin (\frac{2 π t}{4}) = 0.25 \times v_{final} \\ - \frac{4}{2 π} (cos π - cos 0) \times 10 = 0.25 \times v_{f i n a l} \end{array} v_{f i n a l} = 50.92 m / s$

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Force $F (x) = (10 N) \sin (\frac{2 π t}{4 s})$ is exerted on a 250 g particle during the interval $0 s \leq t \leq 2.0 s$ . If the particle starts from rest, what is its speed at t = 2.0 s?

Short Answer

Step by step solution

Step 1. Given information

Step 2. Apply and calculate

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Force F(x)=(10N)sin2πt4sis exerted on a 250 g particle during the interval0s≤t≤2.0s. If the particle starts from rest, what is its speed at t = 2.0 s?

Short Answer

Step by step solution

Step 1. Given information

Step 2. Apply and calculate

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

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Study anywhere. Anytime. Across all devices.

Force $F (x) = (10 N) \sin (\frac{2 π t}{4 s})$ is exerted on a 250 g particle during the interval $0 s \leq t \leq 2.0 s$ . If the particle starts from rest, what is its speed at t = 2.0 s?