A rocket in deep space has an empty mass of 150 kg and exhausts the hot gases of burned fuel at 2500 m/s. It is loaded with 600 kg of fuel, which it burns in 30 s. What is the rocket’s speed 10 s, 20 s, and 30 s after launch?

Short Answer

Expert verified

At t = 10s, speed is equal to 775.5 m/s

At t = 20s, speed is equal to 1905.3 m/s

At t = 30s, speed = vmax = 4023.5 m/s

Step by step solution

01

Step 1. Given information is Empty mass of Rocket mR = 150 kgMass of fuel mFO = 600 kgTime taken to burn the fuel∆t=30 sExhaust speed vex = 2500 m/s

We need to calculate the rocket’s speed 10 s, 20 s, and 30 s after launch.

02

Step 2. Using the rate of burning fuel to find out the rocket's speed after launch.

Rate of burning fuel :

R=dmdt=60030=20kg/sMassoffuelburnedingiventimeinterval:m'=0tR.dt=RtMassoffuelremainingafterthattime:m''=mFO-RTHence,thetotalweightoftherocketis,m=m''+mRm0=mR+mFO=(150+600)kg=750kgWeknowthat,v=vexlnm0mFort=10sm''=mFO-Rt=600-(20×10)=400kgm=m''+mR=(400+150)kg=550kgv=2500ln750550v=775.5m/sFort=20sm''=mFO-Rt=600-20×20=200kgm=m''+mR=(200+150)kg=350kgv=2500ln750350v=1905.3m/sFort=30sm''=mFO-Rt=600-20×30=0ItmeanstherocketwillachievemaximumvelocityUsingformula,vmax=vexlnmFO+mRmRvmax=2500ln750150=4023.5m/s

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