In Problems 66 through 68you are given the equation used to solve a problem. For each of these, you are to

a. Write a realistic problem for which this is the correct equation.

b. Draw the before-and-after pictorial representation.

c. Finish the solution of the problem.

12(1500kg)(5.0m/s)2+(1500kg)9.80m/s2(10m)=12(1500kg)vi2+(1500kg)9.80m/s2(0m)

Short Answer

Expert verified

(a) A 1500kgcar moves up a 10mhigh hill and reaches the top with a speed of 5.0m/s. What initial speed must the car have had at the bottom of the hill?

(b)

(c)Initialspeed=14.9m/s

Step by step solution

01

Given information (part a)

The following equation is given

12(1500kg)(5.0m/s)2+(1500kg)9.80m/s2(10m)=12(1500kg)vi2+(1500kg)9.80m/s2(0m)

02

Explanation (part a)

A 1500kgcar moves up a 10mhigh hill and reaches the top with a speed of 5.0m/s. What initial speed must the car have had at the bottom of the hill?

03

Given information (part b)

The following equation is given

12(1500kg)(5.0m/s)2+(1500kg)9.80m/s2(10m)=12(1500kg)vi2+(1500kg)9.80m/s2(0m)

04

Explanation (part b)

The pictorial representation of the car before and after.

05

Given information (part c)

The following equation is given

12(1500kg)(5.0m/s)2+(1500kg)9.80m/s2(10m)=12(1500kg)vi2+(1500kg)9.80m/s2(0m)

06

Explanation (part c)

The equation can be solved as below:

12(1500kg)(5.0m/s)2+(1500kg)9.80m/s2(10m)=12(1500kg)vi2+(1500kg)9.80m/s2(0m)750kgvi2=18750kgm2/s2+147000kgm2/s2750kgvi2=165750kgm2/s2vi2=165750kgm2/s2750kgvi=221m2/s2vi=14.9m/s

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