Chapter 10: Q.13 (page 256)

A cannon tilted up at a $30^{0}$ angle fires a cannon ball at $80 m / s$ from a top a $10 - m$ -high fortress wall. What is the ball’s impact speed on the ground below?

Short Answer

Expert verified

Ball's impact speed on the ground $v_{i} = 69 m / s$

Step by step solution

Given information

speed of cannon ball $v = 80 m / s$

inclination angle of cannon $θ = 30^{0}$

height of the wall $h = 10 m$

Explanation

Resolving the speed of cannon ball into horizontal and vertical component.

$v_{x} = v \cos (θ) v_{y} = v \sin (θ)$

Therefore, the ball impact speed on ground is given by horizontal component of speed.

$v_{i} = v \cos (θ) \Rightarrow v_{i} = 80 \times \cos (30^{0}) = 69.3 \approx 69 m / s$

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A cannon tilted up at a $30^{0}$ angle fires a cannon ball at $80 m / s$ from a top a $10 - m$ -high fortress wall. What is the ball’s impact speed on the ground below?

Short Answer

Step by step solution

Given information

Explanation

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A cannon tilted up at a 300angle fires a cannon ball at 80m/sfrom a top a 10-m-high fortress wall. What is the ball’s impact speed on the ground below?

Short Answer

Step by step solution

Given information

Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Scientific Method Physics

Force

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Study anywhere. Anytime. Across all devices.

A cannon tilted up at a $30^{0}$ angle fires a cannon ball at $80 m / s$ from a top a $10 - m$ -high fortress wall. What is the ball’s impact speed on the ground below?