Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 10: Q.29 (page 257)

In FIGUREEX10.28, what is the maximum speed a 200gparticle could have at x=2.0m.

It never reach x=6.0m?

Short Answer

Expert verified

Particle's maximum speed is6.32m/s.

Step by step solution

01

Speed : 

It is the change in an object's location with regard to time.

02

Explanation : 

Particle's mass m=200gm=0.2kg,

Formula to determine the kinetic energy of a particle ,

KE=12mv2

KE= kinetic energy,

m= particle's mass

v= particle's velocity.

Consider the graph of potential energy against distance,

The peak of the curve between x=2mandx=6m.

It occurs at x=4m.

Particle's kinetic energy at x=4mmust be 0.

It is if the particle is not allowed to reach at x=6m.

The potential energy difference of localid="1647865759613" x=4mandx=2mwould be the particle's maximum speed so that it can never reach at x=6m.

Potential energy difference,

KE=8-4=4J

Particle's maximum velocity,

KE=12mv24=12×0.2×v2v=6.32m/s

Hence, maximum speed of particle is6.32m/s.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A particle moving along the x-axis is in a system with potential energy U=10/xJ, where x is in m. What is the x-component of the force on the particle atx=2m,5m,and8m?

In Problems 66through 68you are given the equation used to solve a problem. For each of these, you are to

a. Write a realistic problem for which this is the correct equation.

b. Draw the before-and-after pictorial representation.

c. Finish the solution of the problem.

12(0.50kg)vf2+(0.50kg)9.80m/s2(0m)+12(400N/m)(0m)2=12(0.50kg)(0m/s)2+(0.50kg)9.80m/s2(-0.10m)sin30°+12(400N/m)(-0.10m)2

a. With what minimum speed must you toss a 100gball straight up to just touch the 10-m-high roof of the gymnasium if you release the ball 1.5mabove the ground? Solve this problem using energy.

b. With what speed does the ball hit the ground?

What height does a frictionless playground slide need so that a 35 kg child reaches the bottom at a speed of 4.5 m/s?

a. A 50gice cube can slide without friction up and down a 30oslope. The ice cube is pressed against a spring at the bottom of the slope, compressing the spring 10cm. The spring constant is 25N/m. When the ice cube is released, what total distance will it travel up the slope before reversing direction?

b. The ice cube is replaced by a 50gplastic cube whose coefficient of kinetic friction is 0.20. How far will the plastic cube travel up the slope? Use work and energy.

See all solutions

Recommended explanations on Physics Textbooks

Translational Dynamics

Read Explanation

Electrostatics

Read Explanation

Linear Momentum

Read Explanation

Radiation

Read Explanation

Physical Quantities And Units

Read Explanation

Kinematics Physics

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free