A particle moves from A to D in FIGUREEX10.35while experiencing forceF=(6i^+8j^)N. How much work does the force do if the particle follows path (a) ABD, (b) ACD, and (c) AD? Is this a conservative force? Explain.

Short Answer

Expert verified

If particle followed path ABD then work done =50J.

If particle followed path ACD then work done =50J.

If particle followed path AD then work done =50J.

Step by step solution

01

Given information

Force, F=(6i^+8j^)N

Curve followed path,

02

Explanation : 

The force exerted on a mass item that causes it to alter velocity.

When particle follows the path ABD, the work done is

WABD=6×3+8×0+6×0+8×4=50J

When particle follows the path ACD, the work done is

WACD=6×0+8×4+6×3+8×0=50J

When particle follows the path AD, the work done is

WAD=6×3+8×4=50J

Hence, in all the conditions the work done is same. So, the force is a conservative force.

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