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Chapter 2: Q.77 (page 63)

In the problem, you are given the kinematic equation that are used to solve a problem.

  1. Write a realistic problem for which this is the correct equation. Be sure that the answer your problem requests is consistent with the equation given.
  2. Draw the pictorial presentation for your problem.
  3. Finish the solution of the problem.

10m/s2=v0y2-2(9.8m/s2)(10m-0m)

Short Answer

Expert verified

Consider a ball is thrown upward vertically. What will be the launch velocity of the ball after reaching a height of 10m, when the ball is travelling at 10 m/s?

Step by step solution

01

Write the realistic problem representing the given equation:

Consider a ball is thrown upward vertically. What will be the launch velocity of the ball after reaching a height of 10m, when the ball is travelling at 10 m/s?

02

Pictorial presentation of the given problem:

03

Solving the equation:

The given equation is solved as follows:

v0y2=100+196v0y=296m/s=17.2m/s

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Most popular questions from this chapter

Careful measurements have been made of Olympic sprinters

in the 100 meter dash. A quite realistic model is that the sprinter’s

velocity is given by

vx=a(1-e-bt)

where t is in s, vx is in m/s, and the constants a and b are characteristic

of the sprinter. Sprinter Carl Lewis’s run at the 1987

World Championships is modeled with a = 11.81 m/s and

b = 0.6887 s-1.

a. What was Lewis’s acceleration at t = 0 s, 2.00 s, and 4.00 s?

b. Find an expression for the distance traveled at time t.

c. Your expression from part b is a transcendental equation,

meaning that you can’t solve it for t. However, it’s not hard to

use trial and error to find the time needed to travel a specific

distance. To the nearest 0.01 s, find the time Lewis needed to

sprint 100.0 m. His official time was 0.01 s more than your

answer, showing that this model is very good, but not perfect.

A cat is sleeping on the floor in the middle of a 3.0-m-wide room when a barking dog enters with a speed of 1.50 m/s. As the dog enters, the cat (as only cats can do) immediately accelerates at 0.85 m/s2 toward an open window on the opposite side of the room. The dog (all bark and no bite) is a bit startled by the cat and begins to slow down at 0.10 m/s2 as soon as it enters the room. How far is the cat in front of the dog as it leaps through the window?

A car starts from rest at a stop sign. It accelerates at 4.0 m/s2 for 6.0 s, coasts for 2.0 s, and then slows down at a rate of 3.0 m/s2 for the next stop sign. How far apart are the stop signs?

FIGURE EX2.32 shows the acceleration graph for a particle that starts from rest at t = 0 s. What is the particle’s velocity at t = 6 s?

Draw position, velocity, and acceleration graphs for the ball shown in FIGURE P2.44. See Problem 43 for more information.
See all solutions

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