Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 2: Q.85 (page 64)

The Starship Enterprise returns from warp drive to ordinary

space with a forward speed of 50 km/s. To the crew’s great surprise,

a Klingon ship is 100 km directly ahead, traveling in the

same direction at a mere 20 km/s. Without evasive action, the

Enterprise will overtake and collide with the Klingons in just

slightly over 3.0 s. The Enterprise’s computers react instantly to

brake the ship. What magnitude acceleration does the Enterprise

need to just barely avoid a collision with the Klingon ship?

Assume the acceleration is constant.

Hint: Draw a position-versus-time graph showing the motions

of both the Enterprise and the Klingon ship. Let x0 = 0 km be

the location of the Enterprise as it returns from warp drive. How

do you show graphically the situation in which the collision is

“barely avoided”? Once you decide what it looks like graphically,

express that situation mathematically.

Short Answer

Expert verified

The kinematic equations of motion at constant acceleration is given by :

Step by step solution

01

The graph plot:

02

Calculation of the acceleration:

The position function for the starship at 3 seconds is given by :

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

FIGURE Q2.6 shows the position-versus-time graph for a moving

object. At which lettered point or points:

a. Is the object moving the slowest?

b. Is the object moving the fastest?

c. Is the object at rest?

d. Is the object moving to the left?

A cheetah spots a Thomson’s gazelle, its preferred prey, and

leaps into action, quickly accelerating to its top speed of 30 m/s, the highest of any land animal. However, a cheetah can maintain this extreme speed for only 15 s before having to let up. The cheetah is 170 m from the gazelle as it reaches top speed, and the gazelle sees the cheetah at just this instant. With negligible reaction time, the gazelle heads directly away from the cheetah, accelerating at 4.6m/s2for 5.0 s, then running at constant speed. Does the gazelle escape? If so, by what distance is the gazelle in front when the cheetah gives up?

A particle moving along the x-axis has its position described by the function x = 12t 3 + 2t + 12 m, where t is in s. At t = 2 s what are the particle’s (a) position, (b) velocity, and (c) acceleration?

Your goal in the laboratory is to launch a ball of mass m straight up so that it reaches exactly the height h above the top of the launching tube. You and your lab partners will earn fewer points if the ball goes too high or too low. The launch tube uses compressed air to accelerate the ball over a distance d, and you have a table of data telling you how to set the air compressor to achieve the desired acceleration. Find an expression for the acceleration that will earn you maximum points

In the problem, you are given the kinematic equation that are used to solve a problem.

  1. Write a realistic problem for which this is the correct equation. Be sure that the answer your problem requests is consistent with the equation given.
  2. Draw the pictorial presentation for your problem.
  3. Finish the solution of the problem.

64m=0m+32m/s4s-0s+12ax4s-0s2
See all solutions

Recommended explanations on Physics Textbooks

Fluids

Read Explanation

Work Energy and Power

Read Explanation

Atoms and Radioactivity

Read Explanation

Thermodynamics

Read Explanation

Energy Physics

Read Explanation

Torque and Rotational Motion

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free