Chapter 4: Q. 3 (page 105)

Answer Problems 3 through 5 by choosing one of the eight labeled acceleration vectors or selecting option
$I : \vec{a} = \vec{0}$
3. At this instant, the particle has steady speed and is curving to the right. What is the direction of its acceleration?

Short Answer

Expert verified

The acceleration of the particle at that instant is zero.

Step by step solution

Step 1. Introduction

The particle is having steady speed and curving to the right.

Formula to calculate the instantaneous acceleration of a particle is,

$\vec{a} = \frac{d v}{d t}$ - $\vec{a}$ is the instantaneous acceleration of the particle at the give instant.

$\frac{d v}{d t}$ - is the change in velocity of the particle at that instant.

Step 2. Explanation

The particle is having steady speed, so the change in velocity of the particle at any instant is zero. Thus, the acceleration of the particle at that instant is zero.

Therefore, the acceleration of the particle at that instant is zero.

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Answer Problems 3 through 5 by choosing one of the eight labeled acceleration vectors or selecting option
$I : \vec{a} = \vec{0}$
3. At this instant, the particle has steady speed and is curving to the right. What is the direction of its acceleration?

Short Answer

Step by step solution

Step 1. Introduction

Step 2. Explanation

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Answer Problems 3 through 5 by choosing one of the eight labeled acceleration vectors or selecting optionI:a→=0→3. At this instant, the particle has steady speed and is curving to the right. What is the direction of its acceleration?

Short Answer

Step by step solution

Step 1. Introduction

Step 2. Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Rotational Dynamics

Electromagnetism

Oscillations

Radiation

Physical Quantities And Units

Electrostatics

Study anywhere. Anytime. Across all devices.

Answer Problems 3 through 5 by choosing one of the eight labeled acceleration vectors or selecting option
$I : \vec{a} = \vec{0}$
3. At this instant, the particle has steady speed and is curving to the right. What is the direction of its acceleration?