Log out Go to App
Go to App

Learning Materials

Features

Discover

Chapter 4: Q.60 (page 108)

You are asked to consult for the city’s research hospital, where a group of doctors is investigating the bombardment of cancer tumors with high-energy ions. As figure shows, ions are fired directly toward the center of the tumor at speeds of 5.0×106m/s. To cover the entire tumor area, the ions are deflected sideways by passing them between two charged metal plates that accelerate the ions perpendicular to the direction of their initial motion. The acceleration region is 5cmlong, and the ends of the acceleration plates are 1.5mfrom the target. What sideways acceleration is required to deflect an ion 2cmto one side?

Short Answer

Expert verified

a=6.8×1012m/s2

Step by step solution

01

Given information

Speed is v=5.0×106m/s

The acceleration region is L1=5.0cmlong

The ends of the acceleration plates are L2=1.5mfrom the target.

We have the determine the sideways acceleration to deflect an ion d=2.0cmto one side?

02

Calculation

Putting values:

The sideways acceleration is:

a=2v2d2L1L2+L12d=2cm=0.02mL1=5cm=0.05ma=2×(5×106)2m/s×0.02m2×0.05m×1.5m+(0.05m)2a=1×1012m2/s0.15m2+2.5×10-3m2a=2×105m2/s0.1525m2a=6.56×1012m/s2

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Start your free trial

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

A circular track has several concentric rings where people can run at their leisure. Phil runs on the outermost track with radius rP while Annie runs on an inner track with radius rA = 0.80rP. The runners start side by side, along a radial line, and run at the same speed in a counterclockwise direction. How many revolutions has Annie made when Annie’s and Phil’s velocity vectors point in opposite directions for the first time?

Your 64cmdiameter car tire is rotating at 3.5rev/s when suddenly you press down hard on the accelerator. After traveling 200m, the tire’s rotation has increased to 6.0rev/s. What was the tire’s angular acceleration? Give your answer in rad/s2 .

A javelin thrower standing at rest holds the center of the javelin behind her head, then accelerates it through a distance of 70 cm as she throws. She releases the javelin 2.0 m above the ground traveling at an angle of 30° above the horizontal. Top-rated javelin throwers do throw at about a 30° angle, not the 45° you might have expected, because the biomechanics of the arm allow them to throw the javelin much faster at 30° than they would be able to at 45°. In this throw, the javelin hits the ground 62 m away. What was the acceleration of the javelin during the throw? Assume that it has a constant acceleration.

9. A particle moving in the x y planev→=2ti^+3−t2j^m/s

Here t is in s. What is the particle's acceleration vector at t=4s?

Astronauts use a centrifuge to simulate the acceleration of a rocket launch. The centrifuge takes 30sto speed up from rest to its top speed of 1rotation every 1.3s. The astronaut is strapped into a seat 6.0mfrom the axis.

a. What is the astronaut’s tangential acceleration during the first 30s?

b. How many g’s of acceleration does the astronaut experience when the device is rotating at top speed? Each 9.8m/s2of acceleration is1g.
See all solutions

Recommended explanations on Physics Textbooks

Physics of Motion

Read Explanation

Radiation

Read Explanation

Torque and Rotational Motion

Read Explanation

Further Mechanics and Thermal Physics

Read Explanation

Solid State Physics

Read Explanation

Oscillations

Read Explanation
View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free