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Chapter 13: Q. 6 (page 353)

The free-fall acceleration at the surface of planet 1 is 20 m/s2. The radius and the mass of planet 2 are twice those of planet 1. What is g on planet 2?

Short Answer

Expert verified

The value of g on planet 2 is : 10 m/s2

Step by step solution

01

Given Information

The free-fall acceleration at the surface of planet 1 is 20 m/s2

The radius and the mass of planet 2 are twice those of planet 1

02

Explanation

The free fall acceleration is calculated as below

g=GMr2​

g= acceleration due to gravity,

M =mass

G = universal gravitational constant

r= distance from the center of mass of body

role="math" localid="1649255660263" g'g=Gmr2·R2GMg'=g(2M)(2R)2R2Mg'=g2

Substitute the value

g'=20m/s22=10m/s2

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