Chapter 7: Q. 20 (page 178)

Two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. One of the blocks, with a mass of $6.0 k g$ , accelerates downward at $\frac{3}{4} g$ . What is the mass of the other block?

Short Answer

Expert verified

The mass of the second block is $\frac{6}{7} k g$ .

Step by step solution

Given information

The rope is a massless, frictionless, and stationary pulley.

$m_{1} = 6.0 k g a = \frac{3}{4} g$

Explanation

Apply Newton's second law on m₁ and $m_{2}$ with former going down and later going up.

m_{1} a = m_{1} g - T \dots \dots (1) m_{2} a = T - m_{2} g \dots \dots (2)

On adding equation $(1)$ and equation $(2)$

$g [m_{1} - m_{2}] = a [m_{1} + m_{2}] m_{2} = m_{1} \frac{[g - a]}{[g + a]} \dots \dots (3)$

Substituting the given data in the equation $(3)$

localid="1649613361939" $m_{2} = (6 k g) \times \frac{[g - \frac{3}{4} g]}{[g + \frac{3}{4} g]} m_{2} = \frac{6}{7} k g$

The mass of the second block is $\frac{6}{7} k g$ .

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Two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. One of the blocks, with a mass of $6.0 k g$ , accelerates downward at $\frac{3}{4} g$ . What is the mass of the other block?

Short Answer

Step by step solution

Given information

Explanation

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Two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. One of the blocks, with a mass of 6.0kg, accelerates downward at 34g. What is the mass of the other block?

Short Answer

Step by step solution

Given information

Explanation

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Two blocks are attached to opposite ends of a massless rope that goes over a massless, frictionless, stationary pulley. One of the blocks, with a mass of $6.0 k g$ , accelerates downward at $\frac{3}{4} g$ . What is the mass of the other block?