Chapter 7: Q. 25 (page 178)

The $100 k g$ block in FIGURE EX $7.25$ takes $6.0 s$ to reach the floor after being released from rest. What is the mass of the block on the left? The pulley is massless and frictionless.

Short Answer

Expert verified

The acceleration of the $2.0 k g$ blocks is $2.16 m / s^{2}$

Step by step solution

Given information

Mass of right block, $M = 100 k g$

Time taken $t = 6 s$

Distance moved $s = 1 m$

Explanation

Equation of motion for mass m

$T - m g = m a \dots \dots (1)$

Equation of motion for mass M:

$M g - T = M a \dots \dots (2)$

On adding equation $(1) and(2)$

$g (M - m) = a (M + m) m = \frac{M (g - a)}{(g + a)}$

Acceleration a can be calculated as follows.

localid="1649613906426" $s = u t + \frac{1}{2} a t^{2} u = 0 s = 1 m t = 6 s 1 m = 0 + \frac{1}{2} (a) {(6 s)}^{2} a = \frac{2}{36} m / s^{2} a = 0.055 m / s^{2} m = \frac{(100 k g) (9.8 m / s^{2} - 0.055 m / s^{2})}{(9.8 m / s^{2}) + (0.055 m / s^{2})} m = 98.87 k g$

The mass of the block on the left side is $98.87 k g$

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The $100 k g$ block in FIGURE EX $7.25$ takes $6.0 s$ to reach the floor after being released from rest. What is the mass of the block on the left? The pulley is massless and frictionless.

Short Answer

Step by step solution

Given information

Explanation

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The 100kgblock in FIGURE EX7.25takes 6.0sto reach the floor after being released from rest. What is the mass of the block on the left? The pulley is massless and frictionless.

Short Answer

Step by step solution

Given information

Explanation

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Physics of Motion

Mechanics and Materials

Thermodynamics

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Translational Dynamics

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Study anywhere. Anytime. Across all devices.

The $100 k g$ block in FIGURE EX $7.25$ takes $6.0 s$ to reach the floor after being released from rest. What is the mass of the block on the left? The pulley is massless and frictionless.