Bob, who has a mass of, can throw a rock with a speed of 30m/s. The distance through which his hand moves as he accelerates the rock from rest until he releases it is 1.0m.

a. What constant force must Bob exert on the rock to throw it with this speed?

b. If Bob is standing on frictionless ice, what is his recoil speed after releasing the rock?

Short Answer

Expert verified

(a) The force Bob must exert on the rock to throw is 225N

(B) The recoil speed after releasing the rock is0.2m/s

Step by step solution

01

Given information (part a)

Mass of Bob,m=75kg

Weight of rock weight, m=0.5kg

Speed of the rock,30m/s

02

Explanation (part a)

Acceleration :

v2=u2+2asInitialvelocityu=0a=v2-u22sa=30m/s2-021ma=450m/s2

Force exerted on the rock

F=maF=0.5kg450m/s2F=225N

03

Given information (part b)

Mass of Bob, m=75kg

Weight of rock weight, localid="1649688983057" m=0.5kg

Speed of the rock,v=30m/s

04

Explanation (part b)

By conservation of momentum

m1v1+m2v2=0wherem1andv1arethemassandvelocityoftherock,m2andv2arethemassandrecoilvelocityofbob.Sincethespeedofrockisoppositetobob'srecoilspeedv1=-30m/s0.5kg-30m/s+75kgv2=0v2=0.2m/s

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