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Chapter 7: Q. 34 (page 179)

The two blocks in FIGURE $P 7.34$ are sliding down the incline. What is the tension in the massless string?

Short Answer

Expert verified

Tension in the massless string is $0.613 N$ .

Step by step solution

01

Given information

Mass of the block, $m_{1} = 1 k g$

The coefficient of kinetic energy, $μ_{k} = 0.2$

Mass of the block, $m_{2} = 2 k g$

The coefficient of kinetic energy, $μ_{k} = 0.1$

02

Explanation

Consider the equilibrium of force of $1 k g$ block in the direction of the plane

$F_{1} = 1 \times 9.81 \sin 20 - 0.2 \times 1 \times 9.81 \cos 20 + T$

Consider the equilibrium of force of $2 k g$ block in the direction of the plane

$F_{2} = 2 \times 9.81 \sin 20 - 0.1 \times 2 \times 9.81 \cos 20 - T m_{2} a = 4.86 N - T \frac{T + 1.51}{1} \times 2 = 4.86 - T T = 0.613 N$

Tension in the massless string is $0.613 N$ .

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Most popular questions from this chapter

An $80 k g$ spacewalking astronaut pushes off a $640 k g$ satellite, exerting a $100 N$ force for the role="math" localid="1649256566272" $0.50 s$ it takes him to straighten his arms. How far apart are the astronaut and the satellite after $1 m i n .$

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