Chapter 42: Q 18 Exercise (page 1236)

The barium isotope ¹³¹Ba has a half-life of 12 days. A 250 $μ$ mg
sample of ¹³¹Ba is prepared. What is the mass of ¹³¹Ba after
(a) 1 day, (b) 10 days, and (c) 100 days?

Short Answer

Expert verified

Therefore, the mass is

$a.) N = 236 μ g b.) N = 140 μg c.) N = 0.775 μg$

Step by step solution

Given information

$N_{o} = 250 μ g t_{1 / 2} = 12 days$

Explanation (a)

(a)After one day, we will determine N's value:

$N = N_{o} {(\frac{1}{2})}^{t / t_{1 / 2}} N = (250 μ g) {(\frac{1}{2})}^{1 day / 12 days} N = (250 μ g) {(\frac{1}{2})}^{0.0833} N = 236 μ g$

Explanation (b)

(b)After 10 day, we will determine N's value

$N = N_{o} {(\frac{1}{2})}^{t / t_{1 / 2}} N = (250 μ g) {(\frac{1}{2})}^{10 days / 12 days} N = (250 μ g) {(\frac{1}{2})}^{0.833} N = 140 μ g$

Explanation (c)

(c)The N's value after 100 days:

$N = N_{o} {(\frac{1}{2})}^{t / t_{1 / 2}} N = (250 μ g) {(\frac{1}{2})}^{100 days / 12 days} N = (250 μ g) {(\frac{1}{2})}^{8.33} N = 0.775 μ g$

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The barium isotope ¹³¹Ba has a half-life of 12 days. A 250 $μ$ mg
sample of ¹³¹Ba is prepared. What is the mass of ¹³¹Ba after
(a) 1 day, (b) 10 days, and (c) 100 days?

Short Answer

Step by step solution

Given information

Explanation (a)

Explanation (b)

Explanation (c)

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The barium isotope 131Ba has a half-life of 12 days. A 250 μmgsample of 131Ba is prepared. What is the mass of 131Ba after(a) 1 day, (b) 10 days, and (c) 100 days?

Short Answer

Step by step solution

Given information

Explanation (a)

Explanation (b)

Explanation (c)

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Mechanics and Materials

Solid State Physics

Rotational Dynamics

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Electrostatics

Conservation of Energy and Momentum

Study anywhere. Anytime. Across all devices.

The barium isotope ¹³¹Ba has a half-life of 12 days. A 250 $μ$ mg
sample of ¹³¹Ba is prepared. What is the mass of ¹³¹Ba after
(a) 1 day, (b) 10 days, and (c) 100 days?