Chapter 42: Q 22 Exercise (page 1236)

What is the half-life in days of a radioactive sample with 5.0 x 1015

atoms and an activity of 5.0 x 108 Bq?

Short Answer

Expert verified

Therefore the half life in days is80.2days

Step by step solution

01

Given information

N=5.0×1015atomsR=5.0×108Bq

02

Explanation

The activity of a radioactive sample is calculated using

R=r·N(Equation 1.)

The decay rate is:

r=1τr=ln(2)t1/2r=0.693t1/2(Equation2.)

03

Calculation

Substituting the equation (2) in equation (1), we get

R=r·NR=0.693t1/2·Nt1/2·R=(0.693)·Nt1/2=(0.693)·NRt1/2=(0.693)·5.0×1015atoms5.0×108Bqt1/2=6.93×106st1/2=6.93×106s×1day86400st1/2=80.2days

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