Chapter 42: Q 31 Exercise (page 1236)

What is the total energy (in MeV) released in the beta-minus

decay of 3H?

Short Answer

Expert verified

Hence, the energy released is 0.0186298MeV

Step by step solution

01

Given information

mH3=3.016049umHe3=3.016029uΔm=0.000020u

02

Explanation

The decay is given as:

H3He3+e-+v¯

Formula for energy released is:

E=Δmc2

03

Calculations

Substitute the values,

E=(0.000020u)(931.49MeV/u)E=0.0186298MeV

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