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Chapter 42: Q 5 Exercise (page 1236)

Which stable nuclei have a diameter of 7.46 fm?

Short Answer

Expert verified

Therefore, chemical element who has stable isotope of A = 30 is silicon Si.

Step by step solution

01

Given information

$r = 7.46 fm \to 7.46 \times 10^{- 15} m r_{o} = 1.2 fm \to 1.2 \times 10^{- 15} m$

02

Explanation

We have to find value of A from next formula:

$r = 2 r_{o} A^{1 / 3} A^{1 / 3} = \frac{r}{2 r_{o}} A = {(\frac{7.46 fm}{2 \cdot (1.2 fm)})}^{3} A = {(\frac{7.46 fm}{2.4 fm})}^{3} A = (3.108)^{3} A = 30$

Chemical element who has stable isotope of A = 30 is silicon Si.

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