A sample contains radioactive atoms of two types, A and B. Initially there are five times as many A atoms as there are B atoms. Two hours later, the numbers of the two atoms are equal. The half-life of A is 0.50hr. What is the half-life of B?

Short Answer

Expert verified

Half life of B is,1.189hr

Step by step solution

01

Given information

We are given that,

Time is,t=2hr

Half life of A is, localid="1650485209128" t12A=0.50hr

And no. of atoms of A is equal to that of B.

02

Simplify

We know that,

NA=NA012tt12A=NA01220.5=NA0124=NA016

Here, NAis no. of atoms in A after two hours

And localid="1650367252899" NA0is initial no. of atoms in A

As NA=NB

Here,NBis no. of atoms in B

And let initial no. of atoms in B is, NB0

And half life of B is, t12

Therefore,

localid="1650485272574" NA016=NB0×12tt12516=122t12ln516=2t12ln12t12=ln12ln516×2=0.5948×2=1.189hr

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