a. Is the binding energy of a nucleus with A=200more than, less than, or equal to the binding energy of a nucleus with A=60? Explain.

b. Is a nucleus with A=200more tightly bound, less tightly bound, or bound equally tightly as a nucleus with A=60? Explain.

Short Answer

Expert verified

(a) The binding energy of nucleus of mass number A=200is higher than the mass number A=60

(b) The binding energy per nucleon of nucleus withA=200is less than that of the nucleus withA=60

Step by step solution

01

Subpart (a) Part 1:

The binding energy is the energy that holds the nucleus together and it is equal to the mass defect of the nucleus. It is also defined as the energy that required to supply to a nucleus to disassemble it into individual protons and neutrons.

If mass number increases, then the binding energy will also increase.

So, the binding energy of nucleus of mass numberA=200is higher than the mass number A=60.

02

Subpart (b) part 1:

If the number of nucleons increases, then the binding energy per nucleon will also decrease. Since, the binding energy per nucleon is less for lighter nuclides and increase with the mass number.

So, the binding energy per nucleon of nucleus with A=200is less than that of the nucleus with A=60.

Unlock Step-by-Step Solutions & Ace Your Exams!

  • Full Textbook Solutions

    Get detailed explanations and key concepts

  • Unlimited Al creation

    Al flashcards, explanations, exams and more...

  • Ads-free access

    To over 500 millions flashcards

  • Money-back guarantee

    We refund you if you fail your exam.

Over 30 million students worldwide already upgrade their learning with Vaia!

One App. One Place for Learning.

All the tools & learning materials you need for study success - in one app.

Get started for free

Most popular questions from this chapter

See all solutions

Recommended explanations on Physics Textbooks

View all explanations

What do you think about this solution?

We value your feedback to improve our textbook solutions.

Study anywhere. Anytime. Across all devices.

Sign-up for free