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Chapter 42: Q.42 (page 1237)

Use the graph of binding energy to estimate the total energy released if three 4 He nuclei fuse together to form a 12 C nucleus

Short Answer

Expert verified

From the figure 42.6, plot binding energy per nucleon verse mass number given in the text book, the binding energy per nucleon for 4 nucleus approximately is 7.2 MeV and the binding energy per nucleon for 12C nucleus is 7.7MeV.

Step by step solution

01

∆E4He=47.2 MeV            = 28.8MeVThe total binding energy of three4He nuclei is,∆E1=328.8 MeV         =86.4 MeVThe nuclei C12 has 12 nucleons, so the total binding energy of  C12 nucleus is∆E2=127.7 MeV         =92.4 Mev  

The nucleus 4He has 4 nucleons, so the total binding energy of one 4He nucleus is,

02

Step 2

The amount of energy released in the nuclear reaction which involves three 4He nuclei together form a 12C nucleus is,

∆E=E2-E1=92.4MeV-86.4MeV=6.0MeVTherefore,theamountofenergyreleaseis6.0MeV

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