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Chapter 42: Q.42b. (page 1237)

Use the graph of binding energy to estimate the total energy released if three 4Henuclei fuse together to form a12C nucleus.

Short Answer

Expert verified

The amount of energy released is6.0MeV.

Step by step solution

01

Step.1.

From the figure 42.6, plot binding energy per nucleon verse mass number given in the text book, the binding energy per nucleon for 4Henucleus approximately is 7.2MeVand the binding energy per nucleon for 12Cnucleus is 7.7MeV.

The nucleus4Hehas 4 nucleons, so the total binding energy of one 4Henucleus is,

ΔE4He=4(7.2MeV)=28.8MeV

The total binding energy of three4Henuclei is,

ΔE1=(3)(28.8MeV)=86.4MeV

The nucleus 12Chas 12 nucleons, so the total binding energy of 12Cnucleus is,

ΔE2=(12)(7.7MeV)=92.4MeV

02

 Step.2.

The amount of energy released in the nuclear reaction which involves three 4Henuclei fuse together and form a12Cnucleus is,

ΔE=E2−E1=92.4MeV−86.4MeV=6.0MeV

Therefore, the amount of energy released is 6.0MeV.

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