An electron confined in a harmonic potential well emits a 1200nm photon as it undergoes a 32quantum jump. What is the spring constant of the potential well?

Short Answer

Expert verified

Spring constant of potential well =2.243N/m

Step by step solution

01

Step 1. Given information

Energy levels of quantum harmonic oscillator,

En=n-12ω

Here,

ndenotes the state,

=reduced Planck's constant and

ω=classical angular frequency.

02

Step 2. Energy of second level and third level

for second level,

E2=2-12ω

=32ω

for third level,

E3=3-12ω

=52ω

ΔE32=E3-E2

=52ω-32ω

=ω

03

Step 3. For classical angular frequency

Ephoton=hcλphoton

ΔE32=hcλphoton

therefore,

hω=hcλphoton

hω2π=hcλphoton

ω=2πcλphoton

ω=(2π)3×108m/s1200nm10-9m1.0nm

=18.84×108m/s1.2×10-6m

=15.7×1014s-1

04

Step 4. Finding spring constant

ω=km

km=ω2

k=mω2

k=9.1×10-31kg2.5×1014s-12

=2.243N/m

Thus, the spring constant of potential well=2.243N/m

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