a. Derive an expression for λ21, the wavelength of light emitted by a particle in a rigid box during a quantum jump from n=2ton=1.

b. In what length rigid box will an electron undergoing a 21 transition emit light with a wavelength of 694nm? This is the wavelength of a ruby laser

Short Answer

Expert verified

a. λ=8mcL23h

b.E=1.7867eV

Step by step solution

01

Part (a) Step 1: Given information

We have given,

n=2to1

we have to find the wavelength.

02

Simplify

We know that,

E=h28mL2(n22-n12)E=3h28mL2E=hcλλ=8mcL23h

03

Part (b) Step 1: Given information

We have given,

wavelength =694nm

we have to find the energy.

04

Simplify

E=hcλE=1240eV.nm694nmE=1.7867eV

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