A typical electron in a piece of metallic sodium has energy-E0compared to a free electron, where E0is the2.7eV work function of sodium.

a. At what distance beyond the surface of the metal is the electron’s probability density 10%of its value at the surface?

b. How does this distance compare to the size of an atom?

Short Answer

Expert verified

a.1.4A0

Step by step solution

01

Part (a) Step 1: Given information

We have given,

E0=2.7eV

P=10%

we have to find the distance.

02

Simplify

We know that,

Ptunnel=e-2w/η

and,

η=h2π2m(U0-E)η=(6.62×10-34J.s)2π2×9.1×10-31kg(2.7×1.6×10-19J)η=0.12nm

Put this value in probability equation

P=e-2w/(0.12)=0.1-2w0.12=-2.3w=0.14nmw=1.4A0

03

Part (b) Step 1: Given information

We have to find its distance compare with the atom size.

04

Simplify 

Since the found distance is comparable to the size of the atom because the most atoms have to size inA0.

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Show that the penetration distance ηhas units of m.

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