FIGURE EX 40.5is the probability density for an electron in a rigid box. What is the electron’s energy, in eV?

Short Answer

Expert verified

The electron’s energy, in eV is16.9eV.

Step by step solution

01

Given Information

We need to find the electron’s energy, ineV.

02

Simplify

The given graph of the probability density has three antinodes, which means that the wave function also has three antinodes. And we know that the graph of ψnxhas nantinodes .). So, the wave function shown in the graph corresponds to the n=3state. But the energy of an electron in a rigid box is given by:

En=n2h28mL2

Notice that L is given to be0.45nm from the graph, which is the maximum value of x

substitute the numerical values for the quantities in the equation above to find E3

E3=9×6.626×1034Js28×9.11×1031kg×0.45×109m2=2.7×1018J

or in electronvolt

E3=2.7×1018J×1eV1.6×1019JE3=16.9eV

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