Chapter 35: Q. 20 (page 1017)

A sheet of glass has $n_{r e d} = 1.52$ and $n_{v i o l e t} = 1.55$ . A narrow beam of white light is incident on the glass at $30 °$ . What is the angular spread of the light inside the glass?

Short Answer

Expert verified

The angular spread of the light inside the glass is $0.39 °$ .

Step by step solution

Given Information.

We have given the refractive index $n_{r e d} = 1.52$ and $n_{v i o l e t} = 1.55$ .

We need to find the angular spread of light inside the glass.

Diagram

Calculation.

$n_{1} \sin σ_{1} = n_{R} \sin σ_{R}$

$σ_{R} = \sin^{- 1} (\frac{n_{1} \sin σ_{1}}{n_{R}}) = 19.20$

$n_{1} = 1.00$

$σ_{1} = 30$

$n_{R} = 1.52$

$σ_{V} = \sin^{- 1} (\frac{n_{1} \sin σ_{1}}{n_{V}}) = 18.82 c w$

$n_{1} = 1.00$

$σ_{1} = 30$

$n_{V} = 1.55$

$σ = σ_{R} + σ_{V} = 19.20 ° - 18.82 ° = 0.385 °$

Here $n$ is the refractive index and $σ$ is the refractive angle.

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A sheet of glass has $n_{r e d} = 1.52$ and $n_{v i o l e t} = 1.55$ . A narrow beam of white light is incident on the glass at $30 °$ . What is the angular spread of the light inside the glass?

Short Answer

Step by step solution

Given Information.

Diagram

Calculation.

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A sheet of glass has nred=1.52 and nviolet=1.55. A narrow beam of white light is incident on the glass at 30°. What is the angular spread of the light inside the glass?

Short Answer

Step by step solution

Given Information.

Diagram

Calculation.

One App. One Place for Learning.

Most popular questions from this chapter

Recommended explanations on Physics Textbooks

Famous Physicists

Magnetism and Electromagnetic Induction

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Thermodynamics

Study anywhere. Anytime. Across all devices.

A sheet of glass has $n_{r e d} = 1.52$ and $n_{v i o l e t} = 1.55$ . A narrow beam of white light is incident on the glass at $30 °$ . What is the angular spread of the light inside the glass?